3.1006 \(\int \frac {\sqrt [4]{a+b x^4}}{x^{10}} \, dx\)

Optimal. Leaf size=44 \[ \frac {4 b \left (a+b x^4\right )^{5/4}}{45 a^2 x^5}-\frac {\left (a+b x^4\right )^{5/4}}{9 a x^9} \]

[Out]

-1/9*(b*x^4+a)^(5/4)/a/x^9+4/45*b*(b*x^4+a)^(5/4)/a^2/x^5

________________________________________________________________________________________

Rubi [A]  time = 0.01, antiderivative size = 44, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 15, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.133, Rules used = {271, 264} \[ \frac {4 b \left (a+b x^4\right )^{5/4}}{45 a^2 x^5}-\frac {\left (a+b x^4\right )^{5/4}}{9 a x^9} \]

Antiderivative was successfully verified.

[In]

Int[(a + b*x^4)^(1/4)/x^10,x]

[Out]

-(a + b*x^4)^(5/4)/(9*a*x^9) + (4*b*(a + b*x^4)^(5/4))/(45*a^2*x^5)

Rule 264

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[((c*x)^(m + 1)*(a + b*x^n)^(p + 1))/(a
*c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] && EqQ[(m + 1)/n + p + 1, 0] && NeQ[m, -1]

Rule 271

Int[(x_)^(m_)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(x^(m + 1)*(a + b*x^n)^(p + 1))/(a*(m + 1)), x]
- Dist[(b*(m + n*(p + 1) + 1))/(a*(m + 1)), Int[x^(m + n)*(a + b*x^n)^p, x], x] /; FreeQ[{a, b, m, n, p}, x]
&& ILtQ[Simplify[(m + 1)/n + p + 1], 0] && NeQ[m, -1]

Rubi steps

\begin {align*} \int \frac {\sqrt [4]{a+b x^4}}{x^{10}} \, dx &=-\frac {\left (a+b x^4\right )^{5/4}}{9 a x^9}-\frac {(4 b) \int \frac {\sqrt [4]{a+b x^4}}{x^6} \, dx}{9 a}\\ &=-\frac {\left (a+b x^4\right )^{5/4}}{9 a x^9}+\frac {4 b \left (a+b x^4\right )^{5/4}}{45 a^2 x^5}\\ \end {align*}

________________________________________________________________________________________

Mathematica [A]  time = 0.01, size = 31, normalized size = 0.70 \[ \frac {\left (a+b x^4\right )^{5/4} \left (4 b x^4-5 a\right )}{45 a^2 x^9} \]

Antiderivative was successfully verified.

[In]

Integrate[(a + b*x^4)^(1/4)/x^10,x]

[Out]

((a + b*x^4)^(5/4)*(-5*a + 4*b*x^4))/(45*a^2*x^9)

________________________________________________________________________________________

fricas [A]  time = 1.03, size = 38, normalized size = 0.86 \[ \frac {{\left (4 \, b^{2} x^{8} - a b x^{4} - 5 \, a^{2}\right )} {\left (b x^{4} + a\right )}^{\frac {1}{4}}}{45 \, a^{2} x^{9}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^4+a)^(1/4)/x^10,x, algorithm="fricas")

[Out]

1/45*(4*b^2*x^8 - a*b*x^4 - 5*a^2)*(b*x^4 + a)^(1/4)/(a^2*x^9)

________________________________________________________________________________________

giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {{\left (b x^{4} + a\right )}^{\frac {1}{4}}}{x^{10}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^4+a)^(1/4)/x^10,x, algorithm="giac")

[Out]

integrate((b*x^4 + a)^(1/4)/x^10, x)

________________________________________________________________________________________

maple [A]  time = 0.00, size = 28, normalized size = 0.64 \[ -\frac {\left (b \,x^{4}+a \right )^{\frac {5}{4}} \left (-4 b \,x^{4}+5 a \right )}{45 a^{2} x^{9}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((b*x^4+a)^(1/4)/x^10,x)

[Out]

-1/45*(b*x^4+a)^(5/4)*(-4*b*x^4+5*a)/a^2/x^9

________________________________________________________________________________________

maxima [A]  time = 1.34, size = 35, normalized size = 0.80 \[ \frac {\frac {9 \, {\left (b x^{4} + a\right )}^{\frac {5}{4}} b}{x^{5}} - \frac {5 \, {\left (b x^{4} + a\right )}^{\frac {9}{4}}}{x^{9}}}{45 \, a^{2}} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x^4+a)^(1/4)/x^10,x, algorithm="maxima")

[Out]

1/45*(9*(b*x^4 + a)^(5/4)*b/x^5 - 5*(b*x^4 + a)^(9/4)/x^9)/a^2

________________________________________________________________________________________

mupad [B]  time = 1.30, size = 37, normalized size = 0.84 \[ -\frac {{\left (b\,x^4+a\right )}^{1/4}\,\left (5\,a^2+a\,b\,x^4-4\,b^2\,x^8\right )}{45\,a^2\,x^9} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int((a + b*x^4)^(1/4)/x^10,x)

[Out]

-((a + b*x^4)^(1/4)*(5*a^2 - 4*b^2*x^8 + a*b*x^4))/(45*a^2*x^9)

________________________________________________________________________________________

sympy [B]  time = 2.84, size = 109, normalized size = 2.48 \[ - \frac {5 \sqrt [4]{b} \sqrt [4]{\frac {a}{b x^{4}} + 1} \Gamma \left (- \frac {9}{4}\right )}{16 x^{8} \Gamma \left (- \frac {1}{4}\right )} - \frac {b^{\frac {5}{4}} \sqrt [4]{\frac {a}{b x^{4}} + 1} \Gamma \left (- \frac {9}{4}\right )}{16 a x^{4} \Gamma \left (- \frac {1}{4}\right )} + \frac {b^{\frac {9}{4}} \sqrt [4]{\frac {a}{b x^{4}} + 1} \Gamma \left (- \frac {9}{4}\right )}{4 a^{2} \Gamma \left (- \frac {1}{4}\right )} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate((b*x**4+a)**(1/4)/x**10,x)

[Out]

-5*b**(1/4)*(a/(b*x**4) + 1)**(1/4)*gamma(-9/4)/(16*x**8*gamma(-1/4)) - b**(5/4)*(a/(b*x**4) + 1)**(1/4)*gamma
(-9/4)/(16*a*x**4*gamma(-1/4)) + b**(9/4)*(a/(b*x**4) + 1)**(1/4)*gamma(-9/4)/(4*a**2*gamma(-1/4))

________________________________________________________________________________________